Shell programming - Lab Assignments - Part A

Q.1 Non-recursive shell script that accepts any number of arguments and prints them in the reverse order.

Filename:-> 1a.sh

Source Code:-> 

echo "number of arguments are: $#"

len=$#

while [ $len -ne 0 ]

do

eval echo \$$len

len=`expr $len - 1`

done

Output:->

$chmod 777 1a.sh

$./1a.sh a b c

Number of arguments are: 3

c

b

a

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Q.2  Shell script that accepts two file names as arguments, checks if the permissions for these files are identical and if the permissions are identical, outputs the common permissions, otherwise outputs each file name followed by its permissions.

Filename:-> 2a.sh

Source Code:-> 

ls -l $1 | cut -d " " -f1 > file1

ls -l $2 | cut -d " " -f1 > file2

if cmp file1 file2

then 

echo "Both the files have same permission"

cat file1

else

echo "Both the files have different permission"

echo "The permission of the first file $1 is "

cat file1

echo "The permission of the second file $2 is "

cat file2

fi

Output:->

$chmod 777 2a.sh

$cat > file1

This is the first file

$cat > file2

This is the second file

$./2a.sh file1 file2

Both the files have same permission

-rw-r--r--

$chmod 777 file2

$./2a.sh file1 file2

Both the files have different permission 

The permission of the first file file1 is 

-rw-r--r--

The permission of the second file file2 is 

-rwxrwxrwx

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